4=x^2+4bx+13

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Solution for 4=x^2+4bx+13 equation:


Simplifying
4 = x2 + 4bx + 13

Reorder the terms:
4 = 13 + 4bx + x2

Solving
4 = 13 + 4bx + x2

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4bx' to each side of the equation.
4 + -4bx = 13 + 4bx + -4bx + x2

Combine like terms: 4bx + -4bx = 0
4 + -4bx = 13 + 0 + x2
4 + -4bx = 13 + x2

Add '-4' to each side of the equation.
4 + -4 + -4bx = 13 + -4 + x2

Combine like terms: 4 + -4 = 0
0 + -4bx = 13 + -4 + x2
-4bx = 13 + -4 + x2

Combine like terms: 13 + -4 = 9
-4bx = 9 + x2

Divide each side by '-4x'.
b = -2.25x-1 + -0.25x

Simplifying
b = -2.25x-1 + -0.25x

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